24 Aralık 2012 Pazartesi

HACİM VE ALAN HESAPLARI

 
                                                                                                                         15 / 11 / 2012
HACİM VE ALAN HESAPLARI 1
İSMİ
ŞEKİL
HACİM
ALAN
DİKDÖRTGEN PRİZMA
V = a . b . c
     A = 2(a . b + a . c + b . c)
KÜP



             
                  d3
V = a3 = ------
               2.828


      A = 6 . a2 = 3d2






U = Altıgen çevresi
PRİZMA
A  = A1 . h
        A1 = 2,598 . a
A1 = AltIgen yüzey
h = Yükseklik
A = U . h + 2A1
A1 = 2,598 . a
PİRAMİT





      

    

            


                 1
A = ----- . F.h
                3




      

                   a2
hb =√ h2 + ------ L =
                   4
              a2
=√hb2 + -------
                4
                     hbxa
A =F +6 ( -------- )
                        2
F = 2,598.a2 

KONİ
                   1
A = ------- F.h
                 3
A = π.r.s +π.r2
S = √h2 +r2
KESİK KONİ
                           π.h
V = (R2 +r2 +R.r)  -----
                            3

A = (R +r ).π.S +π (R2 +r2)
S = √ h2 + (R −r )2


KÜRE

                   4
V = ---- .π.r      
                   3
           V =4,189.r3
     
           V =0,5236.d3

A = 4 . π . r2

              A = π . d2
KESİK KÜRE

                
                    2
           V = -------  .π.r3
                    3



A = 3π . r2

                                     HACİM VE ALAN HESAPLARI  2
İSMİ
ŞEKİL
HACiM
ALAN
KÜRE PARÇASI

              1
V =π.h2 (r − ---- . h)
               3
    a = 2π.r.h+π(2.r.h - h2)

      A = π.h(4r - h)
KESİK  SİLİNDİR
                   h +h1
   V = π r2 . ----------
                      2
     A= π.r.(h+h1)+F+f
SİLİNDİR
      V = π . r2 . h
         A=2π.r.h+2π.r2
İÇİ BOŞ SİLİNDİR

    V = π . h(R2 — r2)
   A=2.π.h(R+r)+2π.(R2 - r2)
SİLİNDİRİK HALKA
             π.d 2
     V = ---------  .π.D
                4
        A = π . d . π . D

Hiç yorum yok:

Yorum Gönder